[LAD] A bit more MIDI clarification please

[Paul Davis]

On Sun, Oct 5, 2014 at 2:27 PM, Will Godfrey <willgodfrey at musically.me.uk>
wrote:

>
> But, what happens if the synth was registered with jack before the
> sequencer?
> Presumably it is now going to get it's MIDI data *after* it has already
> processed that callback.


JACK clients are executed in the order required by their interconnections.
If client A *sends* data to client B, then client A will always execute
before client B.

if you're silly enough to create a feedback loop, then the  order becomes
undefined.
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