On Fri, Sep 19, 2014 at 5:32 PM, Paul Davis <paul@linuxaudiosystems.com> wrote:

Say we have A, B & C in that order and B&C each take 3mS to return but A takesĀ 
6mS. Does C get booted out even though it was A that was the time hog?

note that nobody but the user can know that A is the time hog. A could be a huge but very efficient signal processor and C could be a badly written delay line. The amount of time they take relative to what they "should" take is not known to JACK (and in most cases, not even to the user).