[Consortium] linuxaudio.org
Marek Peteraj
marpet at naex.sk
Sat Jan 24 08:41:01 EST 2004
On Sat, 2004-01-24 at 11:46, Andrea Glorioso wrote:
> Marek Peteraj <marpet at naex.sk> writes:
>
> >> If we reach a consensus on how to handle this thing, I could even
> >> propose (as a consortium member)
> >
> > You could even propose to the members??
>
> Of course. Linuxaudio.org has been registered for being used by the
> Consortium. As such, I don't have any definitive power over that
> domain, I need to ask for a voting to take place.
See below.
> > No thanks.
>
> As you wish.
>
> >> > You don't have to. Luckily I can *now* read it here:
> >> > http://lists.agnula.org/pipermail/consortium/2004-January/thread.html
> >>
> >> You could read everything even before, you just had to subscribe.
>
> >
> > There was no link. Remember?
>
> If you tried to visit the archives via:
> http://lists.linuxaudio.org/mailman/listinfo/consortium-p
>
> you should have seen all the instructions to subscribe.
Just to remind you.
http://eca.cx/lad/2004/01/0132.html
which was post #41 *after* i have crossposted on LAD.
>
> > Listen. I'm not going to repeat myself over and over again. Almost
> > everything has been said in the LAD linuxaudio.org thread. Basic law
> > background would help you to understand. I don't have the energy to
> > explain things when all i get is your offending tone.
>
> I happen to have a slightly-more-than-basic law background (italian
> civil law) thanks to my studies. I read the "linuxadio.org" thread on
> LAD. Still, I don't get your points. Since you are trying to
> convince me (as a member of the consortium) that my ideas are wrong, I
> suspect the burden of being repetitive and/or more convincing is on
> your shoulders.
>
So you should know that the one who has registered the domain
has got (to quote)"definitive power over that domain".
That isn't the consortium since it isn't a legal entity and can't claim ownership.
Who registered the domain?
>
>
>
> Again: grow a thicker skin.
Learn how to be more polite.
Marek
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