12 Nov
2010
12 Nov
'10
4:14 p.m.
On Nov 12, 2010, at 1:40 AM, Jens M Andreasen wrote:
On Thu, 2010-11-11 at 20:22 -0800, Eric Kampman wrote:
No, turns out the 2nd equation is equivalent to sin(t * pi / 2) I think.
Since power is proportional to signal squared,
this means ..
.. L(t) = cos(t * pi / 2) and R(t) = cos((1 - t) * pi / 2)
I think you misspelled one sin(), no?
It is a complex mul you really want - where L+R is the
real and L-R is
the imaginary. You can have the sin/cos pair very cheaply by using an
LFO that works by rotating iself by some complex constant.
Great idea. Will use. Thanks.