Tim Goetze wrote:
8-bit exponent and no assumption about its value
made, 8 binary
'shift', 7 'or' and 1 'and' statement if i'm not badly
mistaken. and
if i'm not, a branch will probably hurt less.
Three shifts, three copys, three 'or's and an 'and':
copy = value;
value |= copy >> 4;
copy = value;
value |= copy >> 2;
copy = value;
value |= copy >> 1;
value &= 0x01;
elegant indeed (though the exponent is not in the lowest 8 bits so it
needs another shift, no?)