26 Jun
2011
26 Jun
'11
1:27 a.m.
2011/6/26 Gabriel M. Beddingfield <gabrbedd(a)gmail.com>om>:
*headdesk*. Yes... should have been the half-amplitude of
the signal... p = asin( 2*x / A )
I.e. MAX = A/2 and MIN = -A/2
?
Try with
φ = ∆t * f * 2π(rad)
----------------------------------
φ = 1s * 1Hz * 2π => 2π (rad)
φ = 0.5s * 1Hz * 2π => 1π (rad)
φ = 0.25s * 1Hz * 2π => 0.5π (rad) => 90 (deg)
φ = 0.125s * 1Hz * 2π => 1/4π (rad) => 45 (deg)
--
E.R.