31 Jan
2005
31 Jan
'05
5:52 a.m.
On Mon, Jan 31, 2005 at 10:15:56 +0100, Alfons Adriaensen wrote:
On Sun, Jan 30, 2005 at 06:55:45PM -0600, Jack
O'Quin wrote:
Actually there is on fwd, and 3 inv per channel, each xover band is a
seperate inv FFT.
- Steve
In the case of JAMin it was dictated by our
desire to use FFTW rather
than writing our own FFT and trying to figure out how to divide the
computation into relatively equal parts.
For Jamin, you have two channels, each one needs a Fwd and an Inv FFT,
so that would already be 4 approx. equal parts (assuming the FFT dominates
the work to be done).