5 Oct
2014
5 Oct
'14
8:58 p.m.
On Sun, Oct 5, 2014 at 2:27 PM, Will Godfrey <willgodfrey(a)musically.me.uk>
wrote:
But, what happens if the synth was registered with jack before the
sequencer?
Presumably it is now going to get it's MIDI data *after* it has already
processed that callback.
JACK clients are executed in the order required by their interconnections.
If client A *sends* data to client B, then client A will always execute
before client B.
if you're silly enough to create a feedback loop, then the order becomes
undefined.