12 Nov
2010
12 Nov
'10
11:46 p.m.
On Friday 12 November 2010 17:47:08 gene heskett wrote:
On Friday, November 12, 2010 11:43:42 am Eric Kampman
did opine:
Even faster: Use a pre-computed value of pi/2 or pi*0.5. I don't think
compilers will already optimize such a constant part of an equation.
Arnold
On Nov 12, 2010, at 1:40 AM, Jens M Andreasen
wrote:
And is computationally less expensive if you drop the pi / 2 and use
pi * 0.5 as mulls cost less than divs. Or at least this is true if its not
handed off to an FP processor. ;-) On Thu, 2010-11-11 at 20:22 -0800, Eric Kampman
wrote:
No, turns out the 2nd equation is equivalent to sin(t * pi / 2) I think. Since power is proportional to signal squared,
this means ..
.. L(t) = cos(t * pi / 2) and R(t) = cos((1 - t) * pi / 2)
I think you misspelled one sin(), no?