26 Jun
2011
26 Jun
'11
12:44 a.m.
On Saturday, June 25, 2011 05:04:43 pm Emanuel Rumpf wrote:
*headdesk*. Yes... should have been the half-amplitude of
the signal... p = asin( 2*x / A )
I.e. MAX = A/2 and MIN = -A/2
-gabriel
> Assuming
yes:
>
> p = asin( x / A )
>
> Where:
>
> A is the amplitude of the sine wave
you mean the maximal amplitude (-MAX <= x <= +MAX) , I
guess ?