On Sun, Jun 26, 2011 at 11:43:46AM +0200, Jörn Nettingsmeier wrote:
On 06/26/2011 04:17 AM, Fons Adriaensen wrote:
On Sun, Jun 26, 2011 at 12:22:58AM +0200, Jörn
Nettingsmeier wrote:
- Phase is related to delay but it is not the
same thing.
Group delay is again something different. Mixing up all
these is not going to help anyone understand things any
better.
well, i was trying to connect all those buzzwords... but you are right,
it should be done more carefully. let me try again.
*delay* makes the *phase* response curve steeper. it doesn't introduce
any non-linearities in the phase response.
amplitude response over frequency can be interpreted "as-is", but phase
response needs to be looked at with your first-derivative glasses on: a
system comprising a perfect speaker and your perfect ear only has zero
phase when you stick your head into the speaker.
as soon as you move away, the phase drops, the steeper the further you go.
morale: constant amplitude response is what we want. constant phase
response almost never happens, because of delays that creep in. instead,
we want _linear_ phase response.
Right. And 'linear' here means 'without a constant term' - we don't
want our system to be a Hilbert transform for example.
*group* *delay* is a *time* *delay* for a specific
frequency. if you
have a linear-phase system, the group delay is a _constant_: high
frequencies may be phase-shifted by more cycles, but the time it takes
them to arrive is the same as for low frequencies.
i think you get the group delay when you differentiate the phase
response wrt frequency (but don't believe me when i talk calculus...)
Correct. It it the derivative of the phase response w.r.t. angular
frequency (minus that value if your convention is that a delay
corresponds to positive time).
Group delay actually tells us how the 'envelope' of a signal is
modified by nonlinear phase response, something we can easily hear
on any 'percussive' signals.
Let w = 2 * pi * f
Suppose you have some filter that has a non-linear phase
response, e.g.
P(w) = a * w^2 (radians)
The corresponding phase delay is
D(w) = P(w) / w = a * w (seconds)
The group delay is
G(w) = dP(w)/dw = 2 * a * w (seconds)
Now if you have a relatively narrowband signal centered at
some frequency w1, e.g. a 'ping' with a gentle attack, then
it would appear to be delayed by 2 * a * w1, not a * w1,
because what we hear as delay is the delay on the envelope,
not on the 'cycles'.
Ciao,
--
FA