16 Aug
2015
16 Aug
'15
5:04 p.m.
On Sun, 16 Aug 2015 08:06:00 +0000
Fons Adriaensen <fons(a)linuxaudio.org> wrote:
On Sat, Aug 15, 2015 at 10:27:33PM +0100, Will Godfrey
wrote:
Thanks.
Considering this is a mid-range unit V 'standard' motherboard sound, that's
actually rather impressive.
--
Will J Godfrey
http://www.musically.me.uk
Say you have a poem and I have a tune.
Exchange them and we can both have a poem, a tune, and a song.
As a matter of curiosity I wonder if we can work
out what the actual difference
is. Would the Xrun occur when there was a one frame difference, one period, or
1 buffer? It's running at 256 frames per period and 2 periods per buffer. The
xruns occur every 11 minutes (and a few seconds).
If you assume that an xrun occurs when the difference in samples is
one period, then the difference in sample frequency is P / T, with
P the period and T the time in seconds between xruns.
With the values you give:
dF = 256 / (11 * 60) =~ 0.39 Hz.
You can measure this easily using jack_delay (or jack_iodelay).
The change in measured latency, in samples, per second is the
difference in sample rate.
Ciao,