El 20/12/13 15:04, Clemens Ladisch escribiĆ³:
With USB devices, the period boundaries (where
interrupts are supposed
to happen) are not necessarily coincident with the USB frame boundaries
(where interrupts actually happen). This results in delays (jitter) of
up to 1 ms in the timing of period interrupts; with very small buffer
sizes, this increases the risk of underruns greatly. So if, e.g., the
machine is not able to handle "-p 64 -n 2" reliably, increasing the
number of periods to 3 results in lower latency (3*64=192) than
increasing the period size (2*128=256). (Using "-p 96 -n 2" would have
the same latency, but works only if that particular Jack version allows
period sizes that are not a power of two.)
This is a great explanation. Thanks!
--
Roberto Suarez Soto I was born in the back of a black cadillac
And raised by a gypsy queen