31 Oct
2007
31 Oct
'07
11:46 p.m.
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On Mon, Oct 29, 2007 at 10:52:15PM +0100, Fons Adriaensen wrote:
On Sun, Oct 28, 2007 at 06:45:54PM +0100,
leslie.polzer(a)gmx.net wrote:
The impedance of a guitar PU is mostly inductive, i.e. it rises
with frequency. So if you load this with a low impedance the
effect is that of a low-pass filter. That's the simplest case -
in practice the inductance can resonate within the audio band
when connected to a cable (which is capacitive) and this is why
guitar cables can have a distinctive sound.
Anyway, for a guitar you need a high-impedance input, not a
microphone input.
My audio interface has a switch with two settings: "instrument" and
"line" for its XLR/TRS jacks. No "mic" setting, surprisingly.
I'm guessing that would be "line". It also has a "pad" switch for
dealing with hot inputs.
- -ken
You
cannot do that in a sane way - the output of a guitar pickup needs to be
modified (amplified and converted to high impedance) before, otherwise the
signal will suffer (treble loss).
I believe you, but I'd be grateful if someone could explain to me how
one would know that the treble will suffer? I mean, we were talking
about real impedancies, and to determine how the line will react with
respect to certain frequencies we would need the complex part... -----BEGIN PGP SIGNATURE-----
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