8 Jul
2006
8 Jul
'06
6:15 p.m.
Hello everyone,
Maybe not entirely related to music, so forgive me for that. I have been
busy with the following problem for sometime now and I can't seem to
figure it out.
I want to batch create symlinks in the main directory, of all the files
in subdirectories. E.g.
$ls
dir1
dir2
dir3
file1.mp3 -> .dir1/file1.mp3
file2.mp3 -> .dir1/file2.mp3
file3.mp3 -> .dir2/file3.mp3
file4.mp3 -> .dir2/file4.mp3
file5.mp3 -> .dir3/file5.mp3
file6.mp3 -> .dir3/file6.mp3
I tried various shell thingies like:
for i in *.mp3; do ln -s --target-directory=../ $i $i; done
in the subdir, or
for i in ./dir1/*.mp3; do ln -s $i $i;done
with various variations, but it seems impossible to do it this way. What
is the right way to go about this? I know very little Python and some
bash scripting. I want to figure the solution out myself, so any
suggestions/hints related to Python/bash are more than welcome.
Cheers,
Hans
8 Jul
8 Jul
6:28 p.m.
sabato, 08 luglio 2006 alle 22:15:23, Hans ha scritto:
Hello everyone,
Maybe not entirely related to music, so forgive me for that. I have been
busy with the following problem for sometime now and I can't seem to
figure it out.
I want to batch create symlinks in the main directory, of all the files
in subdirectories. E.g.
$ls
dir1
dir2
dir3
file1.mp3 -> .dir1/file1.mp3
file2.mp3 -> .dir1/file2.mp3
file3.mp3 -> .dir2/file3.mp3
file4.mp3 -> .dir2/file4.mp3
file5.mp3 -> .dir3/file5.mp3
file6.mp3 -> .dir3/file6.mp3
I tried various shell thingies like:
for i in *.mp3; do ln -s --target-directory=../ $i $i; done
in the subdir, or
for i in ./dir1/*.mp3; do ln -s $i $i;done
This one works for me:
for i in `ls dir1/*.mp3`; do ln -s $i `basename $i`; done
with various variations, but it seems impossible to do
it this way. What
is the right way to go about this? I know very little Python and some
bash scripting. I want to figure the solution out myself, so any
suggestions/hints related to Python/bash are more than welcome.
Cheers,
Hans
HTH
Ciao
--
Emiliano Grilli
Linux user #209089
http://www.emillo.net
7:15 p.m.
Emiliano Grilli wrote:
sabato, 08 luglio 2006 alle 22:15:23, Hans ha
scritto:
this shell script should also do the job:
#!/bin/bash
find -name \*.mp3 | while read name; do
name="`echo "$name"|sed 's/^\.\///'`"
if ! echo $name|grep "/"> /dev/null; then
continue
fi
ln -s "$name" "` basename "$name"`"
done
Hello everyone,
Maybe not entirely related to music, so forgive me for that. I have been
busy with the following problem for sometime now and I can't seem to
figure it out.
I want to batch create symlinks in the main directory, of all the files
in subdirectories. E.g.
$ls
dir1
dir2
dir3
file1.mp3 -> .dir1/file1.mp3
file2.mp3 -> .dir1/file2.mp3
file3.mp3 -> .dir2/file3.mp3
file4.mp3 -> .dir2/file4.mp3
file5.mp3 -> .dir3/file5.mp3
file6.mp3 -> .dir3/file6.mp3
I tried various shell thingies like:
for i in *.mp3; do ln -s --target-directory=../ $i $i; done
in the subdir, or
for i in ./dir1/*.mp3; do ln -s $i $i;done
This one works for me:
for i in `ls dir1/*.mp3`; do ln -s $i `basename $i`; done
with various variations, but it seems impossible
to do it this way. What
is the right way to go about this? I know very little Python and some
bash scripting. I want to figure the solution out myself, so any
suggestions/hints related to Python/bash are more than welcome.
Cheers,
Hans
HTH
Ciao
8:59 p.m.
--- Hans <hansfong(a)zonnet.nl> wrote:
Hello everyone,
Maybe not entirely related to music, so forgive me for that. I have been
busy with the following problem for sometime now and I can't seem to
figure it out.
I want to batch create symlinks in the main directory, of all the files
in subdirectories. E.g.
$ls
dir1
dir2
dir3
file1.mp3 -> .dir1/file1.mp3
file2.mp3 -> .dir1/file2.mp3
file3.mp3 -> .dir2/file3.mp3
file4.mp3 -> .dir2/file4.mp3
file5.mp3 -> .dir3/file5.mp3
file6.mp3 -> .dir3/file6.mp3
I tried various shell thingies like:
for i in *.mp3; do ln -s --target-directory=../ $i $i; done
in the subdir, or
for i in ./dir1/*.mp3; do ln -s $i $i;done
with various variations, but it seems impossible to do it this way. What
is the right way to go about this? I know very little Python and some
bash scripting. I want to figure the solution out myself, so any
suggestions/hints related to Python/bash are more than welcome.
Cheers,
Hans
How about this?
for x in `find . -type f -name '*.mp3' -print`
do
b=`basename $x`
ln -s $x $b
done
Careful about the quotes, some are backquotes.
I didn't test it, it's just off the top of my head.
You might try it with "echo" before the ln command
just to see what it's going to do before you fire
it off for real.
-- steve
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9 Jul
9 Jul
3:14 a.m.
On Sat, 08 Jul 2006 22:15:23 +0200
Hans <hansfong(a)zonnet.nl> wrote:
Hello everyone,
Maybe not entirely related to music, so forgive me for that. I have been
busy with the following problem for sometime now and I can't seem to
figure it out.
I want to batch create symlinks in the main directory, of all the files
in subdirectories. E.g.
$ls
dir1
dir2
dir3
file1.mp3 -> .dir1/file1.mp3
file2.mp3 -> .dir1/file2.mp3
file3.mp3 -> .dir2/file3.mp3
file4.mp3 -> .dir2/file4.mp3
file5.mp3 -> .dir3/file5.mp3
file6.mp3 -> .dir3/file6.mp3
I tried various shell thingies like:
for i in *.mp3; do ln -s --target-directory=../ $i $i; done
in the subdir, or
for i in ./dir1/*.mp3; do ln -s $i $i;done
find . -iname "foo.mp3" -exec ln -s \{\} ./ \;
Or something. This automatically takes care of whitespaces and other
hassles i think.
Flo
--
Palimm Palimm!
http://tapas.affenbande.org
3:26 a.m.
On Sun, 9 Jul 2006 07:14:37 +0200
Florian Paul Schmidt <mista.tapas(a)gmx.net> wrote:
find . -iname "foo.mp3" -exec ln -s \{\} ./
\;
Errm, damn copy and paste:
find . -iname "*.mp3" -exec ln -s \{\} ./ \;
Flo
--
Palimm Palimm!
http://tapas.affenbande.org
7:17 a.m.
Hallo,
Hans hat gesagt: // Hans wrote:
in the subdir, or
for i in ./dir1/*.mp3; do ln -s $i $i;done
Almost, but you're trying to link a file on itself here ("$i->$i").
Use this instead:
$ for i in ./dir1/*.mp3; do ln -s $i . ;done
or even more general:
$ for i in */* ; do ln -s $i . ; done
Ciao
--
Frank Barknecht _ ______footils.org_ __goto10.org__
11:25 a.m.
Hallo,
Frank Barknecht hat gesagt: // Frank Barknecht wrote:
Almost, but you're trying to link a file on itself
here ("$i->$i").
Use this instead:
$ for i in ./dir1/*.mp3; do ln -s $i . ;done
or even more general:
$ for i in */* ; do ln -s $i . ; done
In case you didn't recognize the difference to your first try: You can
use a directory as the second argument to ln as well, then it will
create a link with the same name as the basename of the file in the
first argument in that directory. All the backtick and find tricks
suggested in the other answers of this thread are nice, but way
overkill to your problem.
Keep it simple, stupid. ;)
Ciao
--
Frank Barknecht _ ______footils.org_ __goto10.org__
1:16 p.m.
Frank Barknecht wrote:
Hallo,
Hans hat gesagt: // Hans wrote:
This I don't understand: so what does the "." stand for?
Hans
P.S. Almost forgot to thank you. This one works and is short too!
in the subdir, or
for i in ./dir1/*.mp3; do ln -s $i $i;done
Almost, but you're trying to link a file on itself here ("$i->$i").
Use this instead:
$ for i in ./dir1/*.mp3; do ln -s $i . ;done
or even more general:
$ for i in */* ; do ln -s $i . ; done
Ciao
2:26 p.m.
This I don't understand: so what does the
"." stand for?
"." is the current directory.
From the man page of "ln"
SYNOPSIS
ln [OPTION]... TARGET [LINK_NAME]
--> ln [OPTION]... TARGET... DIRECTORY
ln [OPTION]... --target-directory=DIRECTORY TARGET...
[...]
When using the second form with more
than one TARGET, the last argument must be a
directory; create links in DIRECTORY to each TARGET.
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2:31 p.m.
On Sun, Jul 09, 2006 at 09:26:23AM -0700, Stephen Cameron wrote:
I think you don't actually need the '.' in this case, so the solution
can be two characters shorter.
Best,
Chris.
-------------------
chris(a)mccormick.cx
http://mccormick.cx
This I don't understand: so what does the
"." stand for?
"." is the current directory.
From the man page of "ln"
SYNOPSIS
ln [OPTION]... TARGET [LINK_NAME]
--> ln [OPTION]... TARGET... DIRECTORY
ln [OPTION]... --target-directory=DIRECTORY TARGET...
[...]
When using the second form with more
than one TARGET, the last argument must be a
directory; create links in DIRECTORY to each TARGET.
8:33 p.m.
Hallo,
Chris McCormick hat gesagt: // Chris McCormick wrote:
I think you don't actually need the '.' in
this case, so the solution
can be two characters shorter.
Or omit the loop instead:
$ ln -s */* .
That must be the shortest one, it's as short as
$ cp -s */* .
Ciao
--
Frank Barknecht _ ______footils.org_ __goto10.org__
3:10 p.m.
On Sun, 9 Jul 2006 11:17:21 +0200
Frank Barknecht <fbar(a)footils.org> wrote:
Hallo,
Hans hat gesagt: // Hans wrote:
Watch out for whitespaces though. If your filenames can contain spaces,
it might be wise to do
export IFS=$'\n'$'\t'
and then do your for-loop. Don't forget to change it back afterwards
though.
Flo
--
Palimm Palimm!
http://tapas.affenbande.org
in the subdir, or
for i in ./dir1/*.mp3; do ln -s $i $i;done
Almost, but you're trying to link a file on itself here ("$i->$i").
Use this instead:
$ for i in ./dir1/*.mp3; do ln -s $i . ;done
or even more general:
$ for i in */* ; do ln -s $i . ; done
8:28 p.m.
Hallo,
Florian Paul Schmidt hat gesagt: // Florian Paul Schmidt wrote:
Alternatively you can quote $i as in:
$ for i in */* ; do ln -s "$i" . ; done
Ciao
--
Frank Barknecht _ ______footils.org_ __goto10.org__
$ for i in */*
; do ln -s $i . ; done
Watch out for whitespaces though. If your filenames can contain spaces,
it might be wise to do
export IFS=$'\n'$'\t'
and then do your for-loop. Don't forget to change it back afterwards
though.
6765
days inactive
6766
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linux-audio-user@lists.linuxaudio.org
13 comments
7 participants
participants (7)
-
Chris McCormick -
Emiliano Grilli -
Florian Paul Schmidt -
Frank Barknecht -
Hans -
Stephen Cameron -
Thomas Ilnseher