11 Sep
2004
11 Sep
'04
11:22 p.m.
Hello,
I need to encode some WAV files into MP3. I'm planning to use Lame.
Lame does not seem to accept wildcards, so I wrote a script-line:
for a in *.wav; do lame --preset cbr 256 $a ; done
But, this encodes *.wav into *.wav.mp3 . How do I make it drop the "wav"
from the name?
(If I need to do it by more elaborate scripting, please do tell me how;
I'm somewhat unfamiliar with bash scripting as yet)
Yours, Mikhail Ramendik
12 Sep
12 Sep
1:28 a.m.
On Sun, Sep 12, 2004 at 05:06:14AM +0400, Mikhail Ramendik wrote:
Hello,
I need to encode some WAV files into MP3. I'm planning to use Lame.
Lame does not seem to accept wildcards, so I wrote a script-line:
for a in *.wav; do lame --preset cbr 256 $a ; done
for a in *.wav; do lame $a `echo $a | sed 's/\(.*\)wav$/\1mp3/'`; done
This one should work as long as your *.wav file names don't contain spaces etc.
For reference, here is a mpp->ogg one-liner that handles those too:
ls -Q *.mpc | sed 's/\(.*\)\.mpc\(.*\)/\$HOME\/bin\/mppdec \1.mpc\2 - | oggenc -o
\1.ogg\2 -/' | sh
cheers,
Christian
--
"Somewhere in Texas... a village is missing its idiot."
7:32 a.m.
On Sun, Sep 12, 2004 at 05:09:06AM +0200, Christian Henz wrote:
for a in *.wav; do lame $a `echo $a | sed
's/\(.*\)wav$/\1mp3/'`; done
less messy (and faster executing) is to let bash do the substituting:
for a in *.wav ; do lame $a ${a/.wav/.mp3} ; done
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2 comments
3 participants
participants (3)
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anahata -
Christian Henz -
Mikhail Ramendik