19 Mar
2011
19 Mar
'11
7:02 p.m.
Hello Everyone!
I'm looking for a completely textual (no even ascii art0 representation of
the DX7 algorithms. I've search the web a bit and the best I found was one of
those ASCII art representations, but I couldn't get much sense out of them. so
does anyone know, or for their wn convenience have, such an overview of the
algorithms?
Kindest regards
Julien
--------
Music was my first love and it will be my last (John Miles)
======== FIND MY WEB-PROJECT AT: ========
http://ltsb.sourceforge.net
the Linux TextBased Studio guide
======= AND MY PERSONAL PAGES AT: =======
http://www.juliencoder.de
19 Mar
19 Mar
9:29 p.m.
Hmm what kind of info are you looking for which isn't contained in the
existing manuals/patch editors/etc graphically? Because Tim
Conrardy's Atari FM site has this page:
http://tamw.atari-users.net/dx7.htm (scroll down for a screenshot of
all the operators and how they feed into each other). It's not text,
but it's a pretty clean representation.
Louis
On Sat, Mar 19, 2011 at 11:05 AM, Julien Claassen <julien(a)c-lab.de> wrote:
Hello Everyone!
I'm looking for a completely textual (no even ascii art0 representation of
the DX7 algorithms. I've search the web a bit and the best I found was one
of those ASCII art representations, but I couldn't get much sense out of
them. so does anyone know, or for their wn convenience have, such an
overview of the algorithms?
Kindest regards
Julien
--------
Music was my first love and it will be my last (John Miles)
======== FIND MY WEB-PROJECT AT: ========
http://ltsb.sourceforge.net
the Linux TextBased Studio guide
======= AND MY PERSONAL PAGES AT: =======
http://www.juliencoder.de
_______________________________________________
Linux-audio-user mailing list
Linux-audio-user(a)lists.linuxaudio.org
http://lists.linuxaudio.org/listinfo/linux-audio-user
9:46 p.m.
On Saturday 19 March 2011 21:29:09 Louis Gorenfeld wrote:
Hmm what kind of info are you looking for which
isn't contained in the
existing manuals/patch editors/etc graphically?
Julien is one of quite a few blind members of this list.
Even ascii-art becomes a problem when you have only one line of braille.
Have fun,
Arnold
10:06 p.m.
Hello1
Sorry, Louis, I completely forgot to mention. I've said this so often here,
I'm afraid of repeating myself to death and boring the readers to death. :-)
Yes so graphics are a problem, since I can't see them. I have the isntrument
myself and I have the manual, but well they all use the grahical
representations. I can see the benefits clearly. It's all very much to the
point and in text you need to explain laboriously and at length.
Warmly yours
Julien
--------
Music was my first love and it will be my last (John Miles)
======== FIND MY WEB-PROJECT AT: ========
http://ltsb.sourceforge.net
the Linux TextBased Studio guide
======= AND MY PERSONAL PAGES AT: =======
http://www.juliencoder.de
10:38 p.m.
Hi Julien!
On Mar 19, 2011, at 11:05 AM, Julien Claassen wrote:
I'm looking for a completely textual (no even
ascii art0
representation of the DX7 algorithms. I've search the web a bit and
the best I found was one of those ASCII art representations, but I
couldn't get much sense out of them. so does anyone know, or for
their wn convenience have, such an overview of the algorithms?
Attached below is the best I have at the moment. It's C code, out of
the hexter sources, but cleaned up a bit.
Each of the six operators are represented by functions, car() for
carriers and mod() for modulators. The first argument to these
functions is the operator number, here OP_1 to OP_6. The second
argument to these functions is the modulation source, usually either
0, or another operator as a mod() function.
The output of each algorithm is defined as the sum of one to six
carrier functions. Stacks of modulators appear as nested second
arguments.
Each algorithm will also have one function, either car_sfb() or
mod_sfb() -- this is the operator that is the source of feedback.
The destination of the feedback appears as 'feedback' in an
operator's second argument. With only a few exceptions, the source
and destination of feedback will be the same operator.
Also, in some algorithms, one operator serves as modulator to more
than one carrier. In these cases, the output of the modulator is
saved in the temporary variable 'i', which then appears in the second
(modulation) argument of the carrier functions.
Hopefully this is useful to you,
-Sean
algorithm 1:
output = (
car(OP_3, mod(OP_4, mod(OP_5, mod_sfb(OP_6,
feedback)))) +
car(OP_1, mod(OP_2, 0))
);
algorithm 2:
output = (
car(OP_3, mod(OP_4, mod(OP_5, mod(OP_6, 0)))) +
car(OP_1, mod_sfb(OP_2, feedback))
);
algorithm 3:
output = (
car(OP_4, mod(OP_5, mod_sfb(OP_6, feedback))) +
car(OP_1, mod(OP_2, mod(OP_3, 0)))
);
algorithm 4:
output = (
car_sfb(OP_4, mod(OP_5, mod(OP_6, feedback))) +
car(OP_1, mod(OP_2, mod(OP_3, 0)))
);
algorithm 5:
output = (
car(OP_5, mod_sfb(OP_6, feedback)) +
car(OP_3, mod(OP_4, 0)) +
car(OP_1, mod(OP_2, 0))
);
algorithm 6:
output = (
car_sfb(OP_5, mod(OP_6, feedback)) +
car(OP_3, mod(OP_4, 0)) +
car(OP_1, mod(OP_2, 0))
);
algorithm 7:
output = (
car(OP_3, mod(OP_5, mod_sfb(OP_6, feedback)) +
mod(OP_4, 0)) +
car(OP_1, mod(OP_2, 0))
);
algorithm 8:
output = (
car(OP_3, mod(OP_5, mod(OP_6, 0)) +
mod_sfb(OP_4, feedback)) +
car(OP_1, mod(OP_2, 0))
);
algorithm 9:
output = (
car(OP_3, mod(OP_5, mod(OP_6, 0)) +
mod(OP_4, 0)) +
car(OP_1, mod_sfb(OP_2, feedback))
);
algorithm 10:
output = (
car(OP_4, mod(OP_6, 0) +
mod(OP_5, 0)) +
car(OP_1, mod(OP_2, mod_sfb(OP_3, feedback)))
);
algorithm 11:
output = (
car(OP_4, mod_sfb(OP_6, feedback) +
mod(OP_5, 0)) +
car(OP_1, mod(OP_2, mod(OP_3, 0)))
);
algorithm 12:
output = (
car(OP_3, mod(OP_6, 0) +
mod(OP_5, 0) +
mod(OP_4, 0)) +
car(OP_1, mod_sfb(OP_2, feedback))
);
algorithm 13:
output = (
car(OP_3, mod_sfb(OP_6, feedback) +
mod(OP_5, 0) +
mod(OP_4, 0)) +
car(OP_1, mod(OP_2, 0))
);
algorithm 14:
output = (
car(OP_3, mod(OP_4, mod_sfb(OP_6, feedback) +
mod(OP_5, 0))) +
car(OP_1, mod(OP_2, 0))
);
algorithm 15:
output = (
car(OP_3, mod(OP_4, mod(OP_6, 0) +
mod(OP_5, 0))) +
car(OP_1, mod_sfb(OP_2, feedback))
);
algorithm 16:
output = car(OP_1, mod(OP_5, mod_sfb(OP_6, feedback)) +
mod(OP_3, mod(OP_4, 0)) +
mod(OP_2, 0));
algorithm 17:
output = car(OP_1, mod(OP_5, mod(OP_6, 0)) +
mod(OP_3, mod(OP_4, 0)) +
mod_sfb(OP_2, feedback));
algorithm 18:
output = car(OP_1, mod(OP_4, mod(OP_5, mod(OP_6, 0))) +
mod_sfb(OP_3, feedback) +
mod(OP_2, 0));
algorithm 19:
i = mod_sfb(OP_6, feedback);
output = (
car(OP_5, i) +
car(OP_4, i) +
car(OP_1, mod(OP_2, mod(OP_3, 0)))
);
algorithm 20:
i = mod_sfb(OP_3, feedback);
output = (
car(OP_4, mod(OP_6, 0) +
mod(OP_5, 0)) +
car(OP_2, i) +
car(OP_1, i)
);
algorithm 21:
i = mod(OP_6, 0);
output = car(OP_5, i) +
car(OP_4, i);
i = mod_sfb(OP_3, feedback);
output += car(OP_2, i) +
car(OP_1, i);
algorithm 22:
i = mod_sfb(OP_6, feedback);
output = (
car(OP_5, i) +
car(OP_4, i) +
car(OP_3, i) +
car(OP_1, mod(OP_2, 0))
);
algorithm 23:
i = mod_sfb(OP_6, feedback);
output = (
car(OP_5, i) +
car(OP_4, i) +
car(OP_2, mod(OP_3, 0)) +
car(OP_1, 0)
);
algorithm 24:
i = mod_sfb(OP_6, feedback);
output = (
car(OP_5, i) +
car(OP_4, i) +
car(OP_3, i) +
car(OP_2, 0) +
car(OP_1, 0)
);
algorithm 25:
i = mod_sfb(OP_6, feedback);
output = (
car(OP_5, i) +
car(OP_4, i) +
car(OP_3, 0) +
car(OP_2, 0) +
car(OP_1, 0)
);
algorithm 26:
output = (
car(OP_4, mod_sfb(OP_6, feedback) +
mod(OP_5, 0)) +
car(OP_2, mod(OP_3, 0)) +
car(OP_1, 0)
);
algorithm 27:
output = (
car(OP_4, mod(OP_6, 0) +
mod(OP_5, 0)) +
car(OP_2, mod_sfb(OP_3, feedback)) +
car(OP_1, 0)
);
algorithm 28:
output = (
car(OP_6, 0) +
car(OP_3, mod(OP_4, mod_sfb(OP_5, feedback))) +
car(OP_1, mod(OP_2, 0))
);
algorithm 29:
output = (
car(OP_5, mod_sfb(OP_6, feedback)) +
car(OP_3, mod(OP_4, 0)) +
car(OP_2, 0) +
car(OP_1, 0)
);
algorithm 30:
output = (
car(OP_6, 0) +
car(OP_3, mod(OP_4, mod_sfb(OP_5, feedback))) +
car(OP_2, 0) +
car(OP_1, 0)
);
algorithm 31:
output = (
car(OP_5, mod_sfb(OP_6, feedback)) +
car(OP_4, 0) +
car(OP_3, 0) +
car(OP_2, 0) +
car(OP_1, 0)
);
algorithm 32:
output = (
car_sfb(OP_6, feedback) +
car(OP_5, 0) +
car(OP_4, 0) +
car(OP_3, 0) +
car(OP_2, 0) +
car(OP_1, 0)
);
11:03 p.m.
Hello Sean!
Thanks very much for this. It's very clear and very readable. Good thing you
wrote the coee, the way you wrote it.
I suppose I can do a bit of beautifying on it and store it. Anyone else
interested in a beautified version? :-)
Only one thing: the _fsb class: Do they feedback on themselves, or where the
word feedback appears/
Warmly yours
Julien
--------
Music was my first love and it will be my last (John Miles)
======== FIND MY WEB-PROJECT AT: ========
http://ltsb.sourceforge.net
the Linux TextBased Studio guide
======= AND MY PERSONAL PAGES AT: =======
http://www.juliencoder.de
11:19 p.m.
On Mar 19, 2011, at 3:06 PM, Julien Claassen wrote:
Only one thing: the _fsb class: Do they feedback on
themselves,
or where the word feedback appears/
The output of the car_sfb() or mod_sfb() function is the source of
the feedback. It then becomes the modulation source for the operator
where 'feedback' appears as the second argument.
Most often the source and destination operators are the same, that
is, they do feed back on themselves. But in the case of two or three
algorithms the feedback loop includes two or more operators.
-Sean
11:22 p.m.
Hey Sean!
Thanks very much. Now I think I can look forward into a more DX7-ish future.
Though it will still be horrible to program. :-)
Kindly yours
Julien
--------
Music was my first love and it will be my last (John Miles)
======== FIND MY WEB-PROJECT AT: ========
http://ltsb.sourceforge.net
the Linux TextBased Studio guide
======= AND MY PERSONAL PAGES AT: =======
http://www.juliencoder.de
11:24 p.m.
On Sat, Mar 19, 2011 at 3:24 PM, Julien Claassen <julien(a)c-lab.de> wrote:
Hey Sean!
Thanks very much. Now I think I can look forward into a more DX7-ish
future. Though it will still be horrible to program. :-)
Kindly yours
Julien
You bet it will still be horrible to program. Always has been.
BTW Julien - I have enjoyed your posts for year and always look
forward to reading about what you are doing. Until today I had
absolutely no idea you were vision impaired in any way.
Cheers,
Mark
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8 comments
5 participants
participants (5)
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Arnold Krille -
Julien Claassen -
Louis Gorenfeld -
Mark Knecht -
Sean Bolton